**Given:**

The sequence is
In=100((1.0025)n−10.0025−n)
. (1)

**Calculation:**

Obtain the first term of the sequence by substituting 1 for *n* in equation (1).

I1=100((1.0025)1−10.0025−1)=100(1.0025−1−0.00250.0025)=100(00.0025)=0

Thus, the first termof the sequence is
I1=$0
.

Obtain the second term of the sequence by substituting 2 for *n* in equation (1).

I2=100((1.0025)2−10.0025−2)=100(0.005006250.0025−2)=100(2.0025−2)=0.25

Thus, the second term of the sequence is
I2=$0.25
.

Obtain the third term of the sequence by substituting 3 for *n* in equation (1).

I3=100((1.0025)3−10.0025−3)=100(0.007518770.0025−3)=100(3.007508−3)=0.75

Thus, the third term of the sequence is
I3=$0.75
.

Obtain the fourth term of the sequence by substituting 4 for *n* in equation (1).

I4=100((1.0025)4−10.0025−4)=100(0.010037560.0025−4)=100(4.015024−4)=1.50

Thus, the fourth term of the sequence is
I4=$1.50
.

Obtain the fifth term of the sequence by substituting 5 for *n* in equation (1).

I5=100((1.0025)5−10.0025−5)=100(0.012562660.0025−5)=100(5.025064−5)=2.51

Thus, the fifth term of the sequence is
I5=$2.51
.

Obtain the sixth term of the sequence by substituting 6 for *n* in equation (1).

I6=100((1.0025)6−10.0025−6)=100(0.015094060.0025−6)=100(6.037624−6)=3.76

Thus, the sixth term of the sequence is
I6=$3.76
.

Therefore, the first six terms of the sequence are
I1=$0, I2=$0.25, I3=$0.75,

I4=$1.50,I6=$2.51 and I6=$3.76
.