Find a formula for the general term $a_{n}$ of the sequence, assuming that the pattern of the first few terms continues.
$\{5,8,11,14,17, \ldots\}$
To find: Formula for general term an of the sequence.
The formula for general term an of the sequence is 2+3n_ .
Given:
The sequence is {5,8,11,14,17,...} .
Here, a1=3,a2=5,a3=8,a4=14 and a5=17
Calculation:
The first term of the sequence can be expressed as follows:
a1=2+3 =2+3⋅1
The second term of the sequence can be expressed as follows:
a2=2+6 =2+3⋅2
The third term of the sequence can be expressed as follows:
a3=2+9 =2+3⋅3
The fourth term of the sequence can be expressed as follows:
a4=2+12 =2+3⋅4
The fifth term of the sequence can be expressed as follows:
a5=2+15 =2+3⋅5
Here, it is observed that every term is greater than the previous term by 3.
Therefore, the formula for general term an of the sequence is 2+3n .