To find: The first five terms of the sequence.

The first five terms of the sequence are 6,6,3,1,14 .

Given:

The sequence is an+1=ann . (1)

The first term of the sequence is a1=6 .

Calculation:

Obtain the second term of the sequence.

Substitute 1 for n in equation (1).

a1+1=a1n

a2=a11 (2)

Substitute 6 for a1 in equation (2).

a2=61=6

Thus, the second term of the sequence is a2=6_ .

Obtain the third term of the sequence.

Substitute 2 for n in equation (1).

a2+1=a22

a3=a22 (3)

Substitute 6 for a2 in equation (3).

a3=62=3

Thus, the third term of the sequence is a3=3_ .

Obtain the fourth term of the sequence.

Substitute 3 for n in equation (1).

a3+1=a33

a4=a33 (4)

Substitute 3 for a3 in equation (4).

  a4=33     =1

Thus, the fourth term of the sequence is a4=1_ .

Obtain the fifth term of the sequence.

Substitute 4 for n in equation (1).

a4+1=a44

  a5=a44 (5)

Substitute 1 for a4 in equation (4).

  a5=14

Thus, the fifth term of the sequence is a5=14_ .

Therefore, the first five terms of the sequence are 6,6,3,1,14 .