**Given:**

The sequence is
an=n2−1n2+1
. (1)

**Calculation:**

Obtain the first term of the sequence.

Substitute 1 for *n* in equation (1).

a1=12−112+1 =1−11+1 =0

Thus, the first term of the sequence is
a1=0_
.

Obtain the second term of the sequence.

Obtain the first term of the sequence.

a2=22−122+1 =4−14+1 =35

Thus, the second term of the sequence is
a2=35_
.

Obtain the third term of the sequence.

Substitute 3 for *n* in equation (1).

a3=32−132+1 =9−19+1 =810

Thus, the third term of the sequence is
a3=810_
.

Obtain the fourth term of the sequence.

Substitute 4 for *n* in equation (1).

a4=42−142+1 =16−116+1 =1517

Thus, the fourth term of the sequence is
a4=1517_
.

Obtain the fifth term of the sequence.

Substitute 5 for *n* in equation (1).

a5=52−152+1 =25−125+1 =2426

Thus, the fifth term of the sequence is
a5=2426_
.

Therefore, the first five terms of the sequence are
0,35,810,1517,2426_
.