**Given:**

The sequence is
an=2n2n+1
. (1)

**Calculation:**

Obtain the first term of the sequence.

Substitute 1 for *n* in equation (1).

a1=212⋅1+1 =22+1 =23

Thus, the first term of the sequence is
a1=23_
.

Obtain the second term of the sequence.

Substitute 2 for *n* in equation (1).

a2=222⋅2+1 =44+1 =45

Thus, the second term of the sequence is
a2=45_
.

Obtain the third term of the sequence.

Substitute 3 for *n* in equation (1).

a3=232⋅3+1 =86+1 =87

Thus, the third term of the sequence is
a3=87_
.

Obtain the fourth term of the sequence.

Substitute 4 for *n* in equation (1).

a4=242⋅4+1 =168+1 =169

Thus, the fourth term of the sequence is
a4=169_
.

Obtain the fifth term of the sequence.

Substitute 5 for *n* in equation (1).

a5=252⋅5+1 =3210+1 =3211

Thus, the fifth term of the sequence is
a5=3211_
.

Therefore, the first five terms of the sequence are
23,45,87,169,3211_
.