#### To determine

**To Evaluate:** the limit limx→1x3−2x2+1x3−1

#### Answer

The value of the following limit is limx→1x3−2x2+1x3−1=−13

#### Explanation

The given limit is in indeterminate form, so we have to use l’Hospital’s Rule, and carry out the simplification.

** ** limx→1x3−2x2+1x3−1 (00Form, we use l'Hospital's Rule)=limx→13x2−4x3x2=3−43=−13

**Conclusion: ** limx→1x3−2x2+1x3−1=−13