the inequality ∫011+e2x dx≥e−1.
We could prove that in the inequality, ∫011+e2x dx≥e−1, the left-hand side is greater than or equal to the right-hand side.
Formulae used: The relation of 1+e2x≥e2x
Consider ∫011+e2x dx≥e−1
Hence, use the formulae of 1+e2x≥e2x
Now according to the given expression, the value of the given expression is
We could prove the inequality ∫011+e2x dx≥e−1