To find: f' in terms of g', given that f(x)=ln|g(x)|
f'(x)=g'(x)g(x)
f(x)=ln|g(x)|
Differentiating w.r.t x, we get
f'(x)=1g(x).g'(x)=g'(x)g(x)
Formula used: ddx(ln|u|)=1u.u'
Conclusion: f'(x)=g'(x)g(x)