To determine

To evaluate : ∫042sds

Answer

∫042sds=15ln2

Explanation

Consider, ∫042sds=[2sln2]04

(Since, we have ∫axdx=axlna+C)

∫042sds=24ln2−20ln2 (Since 24=16;20=1)

=16ln2−1ln2=15ln2

Conclusion: ∫042sds=15ln2