#### To determine

**To find:** Expand the quantity log10x−1x+1

#### Answer

12[log10(x−1)−log10(x+1)]_

#### Explanation

**Given data:** log10x−1x+1

**Formula used:**

log10ab=blog10a

logbx−logby =logb(xy)

** **

**Calculation:**

Consider

y=log10x−1x+1

y=log10(x−1x+1)12

y=12log10(x−1x+1)

y=12[log10(x−1)−log10(x+1)]

Thus, exact value of log10x−1x+1 is 12[log10(x−1)−log10(x+1)]_

**Conclusion:** 12[log10(x−1)−log10(x+1)]_