#### To determine

a)

**To estimate:**

The distance the race car traveled during the given period

#### Answer

2.383 miles

#### Explanation

**1) Concept:**

i. Use the formula

Distance = time * velocity

ii. Convert miles per hour into feet per second.

1 mi/h=52803600 ft/s

**2) Calculation:**

To estimate the distance the race car traveled during 1- minute time period using the velocities at the beginning of the time intervals.

First convert the given velocity into feet per second

Then find distance traveled during each interval.

For interval 0 to 10,

Distance =182.9×52803600≈268.25

For interval 10 to 20,

Distance =168×52803600=246.4

For interval 20 to 30,

Distance =106.6×52803600≈156.36

For interval 30 to 40,

Distance =99.8×52803600≈146.37

For interval 40 to 50,

Distance =124.5×52803600≈182.6

For interval 50 to 60,

Distance =176.1×52803600≈258.28

For interval above 60,

Distance =175.6×52803600≈257.54

The distance traveled during 1- minute time period using the velocities at the beginning of the time periods is

=10268.25+246.4+156.36+146.37+182.6+258.28

=12582.6 ft =2.383 miles

**Conclusion:**

The distance the race car traveled during the 1- minute time period using the velocities at the beginning of the time intervals is 2.383 miles.

#### To determine

b)

**To estimate:**

The distance traveled during 1- minute time period using the velocities at the end of the time periods

#### Answer

2.363 miles

#### Explanation

**1) Concept:**

i. Use the formula

Distance = time * velocity

ii. Convert miles per hour into feet per second

**2) Calculation:**

The distance traveled during 1- minute time period using the velocities at the end of the time periods is

=10246.4+156.36+146.37+182.6+258.28+258.28

=12475.5 ft. =2.363 miles.

**Conclusion:**

The distance traveled during 1-minute time period using the velocities at the end of the time periods is 2.363 miles.

#### To determine

c)

**To explain:**

Are estimates in part ‘a’ and part ‘b’ upper or lower estimates?

#### Answer

No

#### Explanation

The graph is neither increasing nor decreasing. Therefore, it is neither the upper or lower limit.

The upper limit will use the maximum values on the interval, and the lower limit will use the minimum values on the interval.

Upper limit =10268.25+246.4+156.36+182.6+258.28+258.28

=13701.6 ft. =2.595 miles.

Lower limit =10246.4+156.36+146.37+143.37+182.6+257.54

=11356.4 ft. =2.151 miles.

**Conclusion:**

It is neither the upper nor lower limit.