To determine
To find:
∫sin2xsinxdx
Answer
2sinx+C
Explanation
1) Concept:
Apply the formula of indefinite integral and simplify.
2) Formula:
∫cosx dx=sinx+C
sin2θ =2sinθcosθ
3) Calculation:
Consider,
∫sin2xsinxdx Applying the formula,
∫sin2xsinxdx=∫2sinxcosxsinxdx By simplifying,
=2∫cosx dx
By applying the formula of integral, we get
=2sinx+C
Conclusion:
∫sin2xsinxdx=2sinx+C