To determine

To find:

∫sin2xsinxdx

Answer

2sin⁡x+C

Explanation

1)  Concept:

Apply the formula of indefinite integral and simplify.

2) Formula:

∫cos⁡x dx=sin⁡x+C

sin⁡2θ =2sin⁡θcos⁡θ

3) Calculation:

Consider,

∫sin2xsinxdx Applying the formula,

∫sin2xsinxdx=∫2sinxcosxsinxdx By simplifying,

=2∫cos⁡x dx 

By applying the formula of integral, we get

=2sin⁡x+C

Conclusion:

∫sin2xsinxdx=2sin⁡x+C