#### To determine

**To sketch:** The graph of f′ below the graph of *f.*

#### Explanation

From the given graph, it is observed that the graph of *f* contains the horizontal tangents at two points. Let the two points be *A* and *B*.

Note that, the value of the derivative will be zero at the point where the function has the horizontal tangent.

Thus, the graph of f′ will be zero at the points *A* and *B*.

From the point *A* to left, the graph has strictly negative slope which implies that the derivative graph f′ must have a functional value in negative value.

From the point *B* to right, the graph has strictly positive slope which implies that the derivative graph f′ must have a functional value in positive.

**Graph:**

Use the above information and trace the graph of f′(x) as shown below in Figure 1.

Thus, f′ is the required graph.