#### To determine

**To sketch:** The graph of derivative of *f* below the graph of *f.*

#### Explanation

From the given graph, it is observed that the graph of *f* contains the horizontal tangents at the three points. Let the three points be *A*, *B* and *C*.

Note that, the value of the derivative will be zero at the point where the function has the horizontal tangent.

Thus, the graph of f′ will be zero at the points *A*, *B* and *C*.

From the point *A* to left, the slope of the graph *f* is strictly negative which implies that the derivative graph f′ must have a negative functional value.

From the points between *A* and *B*, the slope of the graph *f* is strictly positive which implies that the derivative graph f′ must have a positive functional value.

And, the slope of the graph *f* between the points *B* and *C* is strictly negative, which implies that the derivative graph f′ must have a negative functional value.

From point *C* to right, the slope of the graph *f* is strictly positive, which implies that the derivative graph must have a positive functional value.

Use the above information and obtain the graph of f′(x) as shown below in Figure 1.

From Figure1, it is observed that the function f′(x) passes through the point (0,0).